It's a very common problem for students
and all fresher’s who start their careers as either GET or Management Trainees
in Process Industry to get familiar with terminologies used in process
industries. Here i have tried to simplify and provide most basic level
information when one is at the beginning level of his/her career.
Usually a Line refers to a Pipe and Line
size refers to its ID (Internal Diameter) which can be calculated by using the
continuity equation. Usually we have Fluid normal/standard flow rates & we
are asked to calculate the line size. Now the question is how to do it.
We have a relation
Actual Flow Rate(m3/s) = (Maximum
Allowable Velocity)x(Cross Sectional area of pipe)
i.e. Q = a.v
Where Q = Actual Volumetric Flow Rate
(m3/s)
V = Maximum Allowable
Velocity ≤ Erosion Velocity (m/s)
A = Cross Sectional Area of Pipe (Pi/4 *ID2)
(m2)
ID= Internal Diameter of Pipe (m)
In most of the practical industrial
problems you will have Volumetric Flow rate but you will not have the Maximum
Allowable Velocity or Erosion Velocity (of course no question of Pipe ID, as
you have to calculate this).
Rule
of thumb says that maximum allowable velocity for Gases is 29 m/s while optimum
is considered as 20 m/s. while for liquids minimum velocity should be kept as
0.9 m/s and maximum is 4.5 m/s. Optimum velocity is considered between 1.5 –
2.0 m/s.
Kindly note I have not considered pressure
drop in this line sizing. However; one can control the pressure drop within the
range by increasing or decreasing pipe Diameter on excel file.
Now the important part is that why to do
Line Sizing?
Of Course to control the pressure drop to
keep our pumping cost low & to make sure that a Line has such a diameter
that velocity of fluid flowing inside the line do not crosses maximum allowable
limit (normally Erosion Velocity) to prevent damage of line due to Erosion.
Now in industries, one of the major
problems is that you will never get actual flow rate. Your flow rate will be
given as either standard flow or normal flow for gases. Some of the common
Units are as follows:
1. MMSCFD :
Million Standard Cubic feet per day
2. MMSFH :
Million Standard Cubic Feet Per Hour
3. SCFM :
Standard Cubic feet per minute
4. Sm3/hr : Standard Cubic meter per hour
6. Kg/hr :
Mass Flow Rate
Now important point is to note that these
all flow rates are not actual Volumetric Flow rates.
For 1 to 4 units, convert it to
Sm3/hr and then convert it to actual
flow rates by the help of following Relation
V Actual = (V1 Standard x Standard Pressure x Actual Temperature (Max.)) divided by (Actual
Pressure (Min.) x Standard Temperature)
Here V stands for Volumetric Flow Rate,
Pstd. 1 atm, Tstd. 25 Degc / 298 K
Similarly for Flow rate in Nm3/hr
be converted to Actual Flow Rate using above formulae. Only T Normal will
reduce to 0 Deg C or 273 K.
It is interesting to note that in actual
life problem we will be given a pressure range. For line Sizing one shall
consider minimum pressure and maximum temperature in that range which will
enable us to know largest Pipe ID.
Kindly note that all units should must be
in same convention to cancel each other to give the unit of calculated
parameter.
Let me share an example for simple Line sizing, as next examples very complex.
You have been given Mass Flow Rate of Gas 69084 Kg/hr.
Molecular Weight of Gas is Given as 16.48 kg/kgmol
Temperature is Given as 60 Deg C
Pressure 11.2 bar
Solution: Now remember the formulae for Sizing a Line, You require Volumetric Flow Rate which can be obtained by Dividing Mass flow by Density.
Now the point is how to Calculate Density, Firstly convert your temperature in Rankine which is 599.67 for given case & Pressure in PSI which is 162.4 in this case.
Now if you remember basic chemical equations,
Density= (Mol. Wt x Pressure) / (R x T) which is =(16.48*162.4)*(10.73*599.67)
= 0.416 lb/ft3 which is 6.66 kg/m3.
Hence your Volumetric Flow Rate is = (69084)/(6.66*3600)= 2.88 m3/s
Now take Allowable velocity for gas = 20 m/s
Now your Line Size = Sqrt((Actual Vol. Flow Rate) / (velocity*pie/4)) in m
= SQRT((2.88)/(20*.785)) in m
= 0.428 m
= 428 mm
Hence Appropriate line Size is 450 NB
Let me share an example for simple Line sizing, as next examples very complex.
You have been given Mass Flow Rate of Gas 69084 Kg/hr.
Molecular Weight of Gas is Given as 16.48 kg/kgmol
Temperature is Given as 60 Deg C
Pressure 11.2 bar
Solution: Now remember the formulae for Sizing a Line, You require Volumetric Flow Rate which can be obtained by Dividing Mass flow by Density.
Now the point is how to Calculate Density, Firstly convert your temperature in Rankine which is 599.67 for given case & Pressure in PSI which is 162.4 in this case.
Now if you remember basic chemical equations,
Density= (Mol. Wt x Pressure) / (R x T) which is =(16.48*162.4)*(10.73*599.67)
= 0.416 lb/ft3 which is 6.66 kg/m3.
Hence your Volumetric Flow Rate is = (69084)/(6.66*3600)= 2.88 m3/s
Now take Allowable velocity for gas = 20 m/s
Now your Line Size = Sqrt((Actual Vol. Flow Rate) / (velocity*pie/4)) in m
= SQRT((2.88)/(20*.785)) in m
= 0.428 m
= 428 mm
Hence Appropriate line Size is 450 NB
Given Below are some complex problems, usually encountered in Natural Gas Industry. Kindly refer Rule of Thumb for Pipelines before arriving any conclusion.
If Pressure drop is also to be considered
for Gases case then
When Flow rate is given as mass flow rate
then it can be multiplied by density to get the flow rates. Even if Molecular weight is given, Density
can be calculated at given pressure and Temp.
For liquid fluids, there is not standard
or normal flow. Any Volumetric flow is actual flow. So it can be used directly
in above formulae.
Now it is very obvious that by knowing
actual flow rates of fluid, we can calculate the approximate line size if
pressure drop is not considered.
Queries & comments are welcome... One can also share if have something useful
ReplyDeleteAlso share control valve sizing
ReplyDeleteFor pressure drop case how do u arrive at the formula for calculation of flowrate
ReplyDelete